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Popular >

t(n)=t(n-1)+n(n-1)

Solution

t (n) = t (n - 1) + n (n - 1)

Solution

t = n^{2} - n

Solution steps

t (n) = t (n - 1) + n (n - 1)

Expand

t (n - 1) : n t - t

n t = n t - t + n (n - 1)

Expand

n (n - 1) : n^{2} - n

n t = n t - t + n^{2} - n

Expand

t (n) : n t

n t = n t - t + n^{2} - n

Subtract

n t - t

from both sides

n t - (n t - t) = n t - t + n^{2} - n - (n t - t)

Simplify

t = n^{2} - n

Popular Examples

solvefor a,x=(1+a+b+c)solve for

a, x = (1 + a + b + c)

- 32 = - 7 u + 3 (u + 8)

solvefor x,0=7x-y+13 solve for

x, 0 = 7 x - y + 13

solvefor x,8x+3y-9-8x+y=29 solve for

x, 8 x + 3 y - 9 - 8 x + y = 29

solvefor y,(p^2+q^2)y=z solve for

y, (p^{2} + q^{2}) y = z

Frequently Asked Questions (FAQ)

What is the answer to t(n)=t(n-1)+n(n-1) ?
The answer to t(n)=t(n-1)+n(n-1) is t=n^2-n