What is the answer to 9^{2999}c=999^{999},a=9,^{9999}b=9 ?

The answer to 9^{2999}c=999^{999},a=9,^{9999}b=9 is c=(37^{999})/(3^{3001)}

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9^{2999}c=999^{999},a=9,^{9999}b=9

c = \frac{3 7 ^{999}}{3 ^{3001}}

Solution steps

9^{2999} c = 99 9^{999}

Divide both sides by

9^{2999}

c = \frac{3 7 ^{999}}{3 ^{3001}}

a = ∣ 1 - 3 ∣ + 1

x, x y + 5 x = 4 y + 38

\frac{x + 4}{3} = \frac{31}{2}

x, 5 x - 7 y = 27

x, 2 \cdot f (x - 2) = f

What is the answer to 9^{2999}c=999^{999},a=9,^{9999}b=9 ?
The answer to 9^{2999}c=999^{999},a=9,^{9999}b=9 is c=(37^{999})/(3^{3001)}