What is the answer to z=((2-sqrt(-25)))/((1-sqrt(-36))) ?

The answer to z=((2-sqrt(-25)))/((1-sqrt(-36))) is z= 32/37+i 7/37

Solve for z: z=((2-sqrt(-25)))/((1-sqrt(-36)))

The solution is z= 32/37+i 7/37

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z = \frac{( 2 - - 25 )}{( 1 - - 36 )}

z = \frac{32}{37} + i \frac{7}{37}

Solution steps

z = \frac{( 2 - - 25 )}{( 1 - - 36 )}

Simplify

\frac{2 - - 25}{1 - - 36} : \frac{32}{37} + i \frac{7}{37}

z = \frac{32}{37} + i \frac{7}{37}

7 x + 5 = 10

x = 70 ∣ - 2 ∣

\frac{0.5 x + x}{3} = 0.25 x + 7

m, \frac{m}{5} = \frac{125}{n}

\frac{5 x - 1}{2} = \frac{x + 9}{2}

What is the answer to z=((2-sqrt(-25)))/((1-sqrt(-36))) ?
The answer to z=((2-sqrt(-25)))/((1-sqrt(-36))) is z= 32/37+i 7/37
Solve for z: z=((2-sqrt(-25)))/((1-sqrt(-36)))
The solution is z= 32/37+i 7/37