What are the solutions to the equation 5x^2-21x+4=0 ?

The solutions to the equation 5x^2-21x+4=0 are x=4,x= 1/5

Find the zeros of 5x^2-21x+4=0

The zeros of 5x^2-21x+4=0 are x=4,x= 1/5

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5 x^{2} - 21 x + 4 = 0

x = 4, x = \frac{1}{5}

Solution steps

5 x^{2} - 21 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 21)^{2} - 4 \cdot 5 \cdot 4 = 19

x_{1, 2} = \frac{- ( - 21 ) \pm 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 19}{2 \cdot 5}, x_{2} = \frac{- ( - 21 ) - 19}{2 \cdot 5}

x = \frac{- ( - 21 ) + 19}{2 \cdot 5} : 4

x = \frac{- ( - 21 ) - 19}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{5}

\frac{3}{2} y = \frac{5}{12}

x^{2} + 10 x

100 0^{\frac{2}{3}} 6400 0^{\frac{1}{3}}

- 2 x + 7 \leq 37

x - 9 = 1

What are the solutions to the equation 5x^2-21x+4=0 ?
The solutions to the equation 5x^2-21x+4=0 are x=4,x= 1/5
Find the zeros of 5x^2-21x+4=0
The zeros of 5x^2-21x+4=0 are x=4,x= 1/5