What is the answer to solvefor x,f(x-2)=x+4 ?

The answer to solvefor x,f(x-2)=x+4 is x=(4+2f)/(f-1);\quad f\ne 1

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solvefor x,f(x-2)=x+4

solve for

x, f (x - 2) = x + 4

x = \frac{4 + 2 f}{f - 1}; f \neq = 1

Solution steps

f (x - 2) = x + 4

Expand

f (x - 2) : x f - 2 f

x f - 2 f = x + 4

Move

2 f

to the right side

x f = x + 4 + 2 f

Move

x

to the left side

x f - x = 4 + 2 f

Factor

x f - x : x (f - 1)

x (f - 1) = 4 + 2 f

Divide both sides by

f - 1; f \neq = 1

x = \frac{4 + 2 f}{f - 1}; f \neq = 1

c, k = c + 273

7.8 + 2 (0.75 m + 0.4) = - 6.4 m + 4 (0.5 m - 0.8)

x, \frac{x}{2} - \frac{y}{3} = \frac{1}{6} + y

x, x + y + 2 z = 4

(5^{2} + 2^{3}) \cdot x + 4^{2} = 7^{2}

What is the answer to solvefor x,f(x-2)=x+4 ?
The answer to solvefor x,f(x-2)=x+4 is x=(4+2f)/(f-1);\quad f\ne 1