What is the answer to e=(x+1)(x^2-x+1)-(x-1)(x^2+x+1) ?

The answer to e=(x+1)(x^2-x+1)-(x-1)(x^2+x+1) is No Solution

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e=(x+1)(x^2-x+1)-(x-1)(x^2+x+1)

e = (x + 1) (x^{2} - x + 1) - (x - 1) (x^{2} + x + 1)

No Solution

Solution steps

e = (x + 1) (x^{2} - x + 1) - (x - 1) (x^{2} + x + 1)

Switch sides

(x + 1) (x^{2} - x + 1) - (x - 1) (x^{2} + x + 1) = e

Expand

(x + 1) (x^{2} - x + 1) - (x - 1) (x^{2} + x + 1) : 2

2 = e

The sides are not equal

No Solution

x, 3 x - 5 y + 6 = 0

x, f = \frac{1}{3} f

1.6 = \frac{y}{1.5}

x, y - 3 = 5 (x - 9)

v, v + f = a + 2

What is the answer to e=(x+1)(x^2-x+1)-(x-1)(x^2+x+1) ?
The answer to e=(x+1)(x^2-x+1)-(x-1)(x^2+x+1) is No Solution