What is the answer to solvefor x,z=f(y+2x)+g(y-3x) ?

The answer to solvefor x,z=f(y+2x)+g(y-3x) is x=(z-yf-yg)/(2f-3g);\quad 2f-3g\ne 0

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solvefor x,z=f(y+2x)+g(y-3x)

solve for

x, z = f (y + 2 x) + g (y - 3 x)

x = \frac{z - y f - y g}{2 f - 3 g}; 2 f - 3 g \neq = 0

Solution steps

z = f (y + 2 x) + g (y - 3 x)

Switch sides

f (y + 2 x) + g (y - 3 x) = z

Expand

f (y + 2 x) : y f + 2 x f

y f + 2 x f + g (y - 3 x) = z

Expand

g (y - 3 x) : y g - 3 xg

y f + 2 x f + y g - 3 xg = z

Move

y f

to the right side

2 x f + y g - 3 xg = z - y f

Move

y g

to the right side

2 x f - 3 xg = z - y f - y g

Factor

2 x f - 3 xg : x (2 f - 3 g)

x (2 f - 3 g) = z - y f - y g

Divide both sides by

2 f - 3 g; 2 f - 3 g \neq = 0

x = \frac{z - y f - y g}{2 f - 3 g}; 2 f - 3 g \neq = 0

x - 45 = 128

t (n) = 3 t (\frac{n}{3}) + lo g_{10} (n)

- 2 x - 2 x - 0.2 x = 1 - 0.5 x

\frac{( x - 2 )}{5} + \frac{x}{4} = 2

y, (a + p) \cdot y = q (2 a - q)

What is the answer to solvefor x,z=f(y+2x)+g(y-3x) ?
The answer to solvefor x,z=f(y+2x)+g(y-3x) is x=(z-yf-yg)/(2f-3g);\quad 2f-3g\ne 0