What is the answer to solvefor x,p^2+q^2=x+y ?

The answer to solvefor x,p^2+q^2=x+y is x=p^2+q^2-y

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solvefor x,p^2+q^2=x+y

solve for

x, p^{2} + q^{2} = x + y

x = p^{2} + q^{2} - y

Solution steps

p^{2} + q^{2} = x + y

Switch sides

x + y = p^{2} + q^{2}

Move

y

to the right side

x = p^{2} + q^{2} - y

n, f = 2 f (n - 1)

x, 3 x + 4 y = - 10

(\frac{x}{( 3 + 4 i )}) + (\frac{( 2 x + 5 i )}{( 1 - 2 i )}) = 2 + 2 i

- 9 x - 6 = - 15.5 x + 46

(2 - 2) = (6 y)

What is the answer to solvefor x,p^2+q^2=x+y ?
The answer to solvefor x,p^2+q^2=x+y is x=p^2+q^2-y