What are the solutions to the equation 4-x^2=2-x ?

The solutions to the equation 4-x^2=2-x are x=-1,x=2

Find the zeros of 4-x^2=2-x

The zeros of 4-x^2=2-x are x=-1,x=2

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4 - x^{2} = 2 - x

x = - 1, x = 2

Solution steps

4 - x^{2} = 2 - x

Move

x

to the left side

4 - x^{2} + x = 2

Move

2

to the left side

- x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 ( - 1 )}, x_{2} = \frac{- 1 - 3}{2 ( - 1 )}

x = \frac{- 1 + 3}{2 ( - 1 )} : - 1

x = \frac{- 1 - 3}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

980 \cdot \frac{4}{7}

\frac{1200}{4}

(5 + 3) (5 - 3)

z^{2} - 5 ∣ z ∣ + 6 = 0

\frac{3}{2} 8

What are the solutions to the equation 4-x^2=2-x ?
The solutions to the equation 4-x^2=2-x are x=-1,x=2
Find the zeros of 4-x^2=2-x
The zeros of 4-x^2=2-x are x=-1,x=2