What is the answer to solvefor x,x(z)= 1/(((z-1/4)(z-1/z))) ?

The answer to solvefor x,x(z)= 1/(((z-1/4)(z-1/z))) is x= 4/((4z-1)(z^2-1));\quad z\ne 0

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solvefor x,x(z)= 1/(((z-1/4)(z-1/z)))

solve for

x, x (z) = \frac{1}{( ( z - \frac{1}{4} ) ( z - \frac{1}{z} ) )}

x = \frac{4}{( 4 z - 1 ) ( z ^{2} - 1 )}; z \neq = 0

Solution steps

x (z) = \frac{1}{( ( z - \frac{1}{4} ) ( z - \frac{1}{z} ) )}

x z = \frac{1}{( z - \frac{1}{4} ) ( z - \frac{1}{z} )}

Divide both sides by

z; z \neq = 0

x = \frac{4}{( 4 z - 1 ) ( z ^{2} - 1 )}; z \neq = 0

x - 2 (a^{2} + b^{2}) \cdot x + (a^{2} - b^{2})^{2} = 0

x, 93 x + 141 y = 45

x, \frac{1}{5} x + \frac{5}{8} y = \frac{41}{2}

(3 n + 15) \cdot x = (2 m - 8)

1.5 x = 3

What is the answer to solvefor x,x(z)= 1/(((z-1/4)(z-1/z))) ?
The answer to solvefor x,x(z)= 1/(((z-1/4)(z-1/z))) is x= 4/((4z-1)(z^2-1));\quad z\ne 0