What is the answer to (5x-1)^2-7x(3x-2)=(2x-3)^2 ?

The answer to (5x-1)^2-7x(3x-2)=(2x-3)^2 is x= 1/2

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(5x-1)^2-7x(3x-2)=(2x-3)^2

(5 x - 1)^{2} - 7 x (3 x - 2) = (2 x - 3)^{2}

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

(5 x - 1)^{2} - 7 x (3 x - 2) = (2 x - 3)^{2}

Expand

(5 x - 1)^{2} - 7 x (3 x - 2) : 4 x^{2} + 4 x + 1

Expand

(2 x - 3)^{2} : 4 x^{2} - 12 x + 9

4 x^{2} + 4 x + 1 = 4 x^{2} - 12 x + 9

Move

1

to the right side

4 x^{2} + 4 x = 4 x^{2} - 12 x + 8

Subtract

4 x^{2} - 12 x

from both sides

4 x^{2} + 4 x - (4 x^{2} - 12 x) = 4 x^{2} - 12 x + 8 - (4 x^{2} - 12 x)

Simplify

16 x = 8

Divide both sides by

16

x = \frac{1}{2}

x, 2 x - 5 y = 2

0.9 x + 0.5 = - 0.01 x

a, a \cdot x^{2} + 3 x - 33 = 3 x

x, 13 x y + 5 x z = 8 w - 4

x, y = 5 \frac{x}{u} - 6 \frac{x}{v}

What is the answer to (5x-1)^2-7x(3x-2)=(2x-3)^2 ?
The answer to (5x-1)^2-7x(3x-2)=(2x-3)^2 is x= 1/2
Solve for x: (5x-1)^2-7x(3x-2)=(2x-3)^2
The solution is x= 1/2