What is the answer to e=(a+2)^2-(a-2)^2-(a+1)(1-a)-(a+4)^2+20 ?

The answer to e=(a+2)^2-(a-2)^2-(a+1)(1-a)-(a+4)^2+20 is No Solution

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e=(a+2)^2-(a-2)^2-(a+1)(1-a)-(a+4)^2+20

e = (a + 2)^{2} - (a - 2)^{2} - (a + 1) (1 - a) - (a + 4)^{2} + 20

No Solution

Solution steps

e = (a + 2)^{2} - (a - 2)^{2} - (a + 1) (1 - a) - (a + 4)^{2} + 20

Switch sides

(a + 2)^{2} - (a - 2)^{2} - (a + 1) (1 - a) - (a + 4)^{2} + 20 = e

Move

20

to the right side

(a + 2)^{2} - (a - 2)^{2} - (a + 1) (1 - a) - (a + 4)^{2} = e - 20

Expand

(a + 2)^{2} - (a - 2)^{2} - (a + 1) (1 - a) - (a + 4)^{2} : - 17

- 17 = e - 20

The sides are not equal

No Solution

f = 5 (\frac{2}{5}) + 3

5 + 26 = a + 3

x, - 2 (x + 4) + 3 y = 5

\frac{( 1 - 2 x )}{7} - \frac{( 2 - 3 x )}{8} = \frac{3}{2} + \frac{x}{4}

a + x + b = 12

What is the answer to e=(a+2)^2-(a-2)^2-(a+1)(1-a)-(a+4)^2+20 ?
The answer to e=(a+2)^2-(a-2)^2-(a+1)(1-a)-(a+4)^2+20 is No Solution