What is the answer to solvefor x,y[n]=x[n]*[n-2] ?

The answer to solvefor x,y[n]=x[n]*[n-2] is x= y/(n-2);\quad n\ne 0,n\ne 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y[n]=x[n]*[n-2]

solve for

x, y [n] = x [n] \cdot [n - 2]

x = \frac{y}{n - 2}; n \neq = 0, n \neq = 2

Solution steps

y [n] = x [n] [n - 2]

Switch sides

x [n] [n - 2] = y [n]

x [n] [n - 2] = n y

Divide both sides by

n (n - 2); n \neq = 0, n \neq = 2

x = \frac{y}{n - 2}; n \neq = 0, n \neq = 2

4 (2 m - 1) = 2 (m - 3)

\frac{x - 1}{2} = \frac{21}{3}

380 + (- 9 t) = 420 + (- 13) t

x = \frac{5}{( 5 + 4 )}

b = \frac{( 6 \cdot 1 0 ^{12} \cdot 35 \cdot 1 0 ^{8} )}{( 14 \cdot ( 1 0 ^{5} ) ^{3} )}

What is the answer to solvefor x,y[n]=x[n]*[n-2] ?
The answer to solvefor x,y[n]=x[n]*[n-2] is x= y/(n-2);\quad n\ne 0,n\ne 2