What is the answer to solvefor x, x/2+y/3+z/4 =1 ?

The answer to solvefor x, x/2+y/3+z/4 =1 is x=2-(2y)/3-z/2

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solvefor x, x/2+y/3+z/4 =1

solve for

x, \frac{x}{2} + \frac{y}{3} + \frac{z}{4} = 1

x = 2 - \frac{2 y}{3} - \frac{z}{2}

Solution steps

\frac{x}{2} + \frac{y}{3} + \frac{z}{4} = 1

Move

\frac{y}{3}

to the right side

\frac{x}{2} + \frac{z}{4} = 1 - \frac{y}{3}

Move

\frac{z}{4}

to the right side

\frac{x}{2} = 1 - \frac{y}{3} - \frac{z}{4}

Multiply both sides by

2

x = 2 - \frac{2 y}{3} - \frac{z}{2}

\frac{( 3 x )}{4} - \frac{( 2 x + 5 )}{3} = \frac{5}{2}

1 (i) 2 (3 - 2 x) = 13

x, f = - f (1 - x)

a, a (x) = x^{5} + 5 x^{4} + 7 x^{3} - x^{2} - 8 x - 4

z = (1 + i)^{10}

What is the answer to solvefor x, x/2+y/3+z/4 =1 ?
The answer to solvefor x, x/2+y/3+z/4 =1 is x=2-(2y)/3-z/2