What is the answer to solvefor g,3^logax+3x^{log_{a}(3)}=2 ?

The answer to solvefor g,3^logax+3x^{log_{a}(3)}=2 is g=(2-3x^{log_{a}(3)})/(3^laox)

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solvefor g,3^logax+3x^{log_{a}(3)}=2

solve for

g, 3^{l} o g a x + 3 x^{l o g_{a} (3)} = 2

g = \frac{2 - 3 x ^{l o g_{a} (3)}}{3 ^{l} a o x}

Solution steps

3^{l} o g a x + 3 x^{l o g_{a} (3)} = 2

Move

3 x^{l o g_{a} (3)}

to the right side

3^{l} o g a x = 2 - 3 x^{l o g_{a} (3)}

Divide both sides by

3^{l} o a x

g = \frac{2 - 3 x ^{l o g_{a} (3)}}{3 ^{l} a o x}

p = 800 \cdot (1 + \frac{3}{100})^{8}

x, 5 x + 3 y - 11 z = 13

- 0.05 (x + 4) (0 - 30) = 0

x, 5 x + 2 y - 4 = 0

x, 4 x - 2 y - 6 = 7 + 2 x + 7 y

What is the answer to solvefor g,3^logax+3x^{log_{a}(3)}=2 ?
The answer to solvefor g,3^logax+3x^{log_{a}(3)}=2 is g=(2-3x^{log_{a}(3)})/(3^laox)