What is the answer to (x+4)^3-x^2(x+12)=16 ?

The answer to (x+4)^3-x^2(x+12)=16 is x=-1

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(x+4)^3-x^2(x+12)=16

(x + 4)^{3} - x^{2} (x + 12) = 16

x = - 1

Solution steps

(x + 4)^{3} - x^{2} (x + 12) = 16

Expand

(x + 4)^{3} - x^{2} (x + 12) : 48 x + 64

48 x + 64 = 16

Move

64

to the right side

48 x = - 48

Divide both sides by

48

x = - 1

x, x - 4 = 9 (y - 4)

f = 8.5 + 1.4 (0.025 - 0.044)

g (- 4) = 2 (- 4) 2 - 3 (- 4)

a, 3 a - 4 b + 6 a = 9 a - 4 b

d \cdot (- 15) [(- 7) \cdot 4] = [(- 15) \cdot x] \cdot 4

What is the answer to (x+4)^3-x^2(x+12)=16 ?
The answer to (x+4)^3-x^2(x+12)=16 is x=-1
Solve for x: (x+4)^3-x^2(x+12)=16
The solution is x=-1