What is 1+4/(x-2)<= 1/(x-1) ?

The solution to 1+4/(x-2)<= 1/(x-1) is x=0\lor 1<x<2

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1+4/(x-2)<= 1/(x-1)

1 + \frac{4}{x - 2} \leq \frac{1}{x - 1}

x = 0 or 1 < x < 2

Interval Notation

x = 0 \cup (1, 2)

Solution steps

1 + \frac{4}{x - 2} \leq \frac{1}{x - 1}

Rewrite in standard form

\frac{x ^{2}}{( x - 2 ) ( x - 1 )} \leq 0

Identify the intervals

x = 0 or 1 < x < 2

\frac{5 + 3}{5 - 3}

2 n + 6

- 8 (x + 9) = 2 (x + 4)

x^{2} - 3 x - 4 = 0

\frac{1}{2} (1)^{3}

What is 1+4/(x-2)<= 1/(x-1) ?
The solution to 1+4/(x-2)<= 1/(x-1) is x=0\lor 1<x<2