What is the answer to ((3t-2))/4-((2t+3))/3 = 2/3-t ?

The answer to ((3t-2))/4-((2t+3))/3 = 2/3-t is t=2

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((3t-2))/4-((2t+3))/3 = 2/3-t

\frac{( 3 t - 2 )}{4} - \frac{( 2 t + 3 )}{3} = \frac{2}{3} - t

t = 2

Solution steps

\frac{( 3 t - 2 )}{4} - \frac{( 2 t + 3 )}{3} = \frac{2}{3} - t

\frac{3 t - 2}{4} - \frac{2 t + 3}{3} = \frac{2}{3} - t

Multiply by LCM

3 (3 t - 2) - 4 (2 t + 3) = 8 - 12 t

Expand

3 (3 t - 2) - 4 (2 t + 3) : t - 18

t - 18 = 8 - 12 t

Move

18

to the right side

t = - 12 t + 26

Move

12 t

to the left side

13 t = 26

Divide both sides by

13

t = 2

- 5 (x + 2) + 5 = - 8 (x - 3)

x = \frac{( ( 2.102 ) ^{2} \cdot 3 \cdot 142 )}{( ( 2 \cdot 8 ) ^{2} )}

\frac{12 x \cdot 2 - 8 x + 11}{3} = 0

x = \frac{- 12}{28}

a (n + 2) - 5 a (n + 1) + 6 a (n) = 2

What is the answer to ((3t-2))/4-((2t+3))/3 = 2/3-t ?
The answer to ((3t-2))/4-((2t+3))/3 = 2/3-t is t=2
Solve for t: ((3t-2))/4-((2t+3))/3 = 2/3-t
The solution is t=2