What is the answer to solvefor n,n(x)=2x^2+4-6x-2x^3+x^2+1 ?

The answer to solvefor n,n(x)=2x^2+4-6x-2x^3+x^2+1 is n=(-2x^3+3x^2-6x+5)/x ;\quad x\ne 0

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solvefor n,n(x)=2x^2+4-6x-2x^3+x^2+1

solve for

n, n (x) = 2 x^{2} + 4 - 6 x - 2 x^{3} + x^{2} + 1

n = \frac{- 2 x ^{3} + 3 x ^{2} - 6 x + 5}{x}; x \neq = 0

Solution steps

n (x) = 2 x^{2} + 4 - 6 x - 2 x^{3} + x^{2} + 1

Group like terms

n x = - 2 x^{3} + 2 x^{2} + x^{2} - 6 x + 4 + 1

Add similar elements:

2 x^{2} + x^{2} = 3 x^{2}

n x = - 2 x^{3} + 3 x^{2} - 6 x + 4 + 1

Add the numbers:

4 + 1 = 5

n x = - 2 x^{3} + 3 x^{2} - 6 x + 5

Divide both sides by

x; x \neq = 0

n = \frac{- 2 x ^{3} + 3 x ^{2} - 6 x + 5}{x}; x \neq = 0

f, - f \cdot (x) = (4 - x)^{3}

a, a + b - 7 = 10

z = \frac{( 2 - 2 i )}{( 2 + 2 i )}

x, 5 x + 4 y = 42

73 x + 1 = 5 x + 10

What is the answer to solvefor n,n(x)=2x^2+4-6x-2x^3+x^2+1 ?
The answer to solvefor n,n(x)=2x^2+4-6x-2x^3+x^2+1 is n=(-2x^3+3x^2-6x+5)/x ;\quad x\ne 0