What is the answer to solvefor x,yn=0.2y[n-1]+x[n] ?

The answer to solvefor x,yn=0.2y[n-1]+x[n] is x=(y(4n+1))/(5n);\quad n\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,yn=0.2y[n-1]+x[n]

solve for

x, y n = 0.2 y [n - 1] + x [n]

x = \frac{y ( 4 n + 1 )}{5 n}; n \neq = 0

Solution steps

y n = 0.2 y [n - 1] + x [n]

Switch sides

0.2 y [n - 1] + x [n] = y n

0.2 y (n - 1) + n x = y n

Multiply both sides by

10

2 y (n - 1) + 10 n x = y n \cdot 10

Move

2 y (n - 1)

to the right side

10 n x = 8 n y + 2 y

Divide both sides by

10 n; n \neq = 0

x = \frac{y ( 4 n + 1 )}{5 n}; n \neq = 0

y, 2 y + 6 = x

x, 5 x \cdot 6 y = 12

a, c + d = 4 a - b

z = \frac{( - 3 3 + 3 i )}{2}

x, - 4 x + y = - 9

What is the answer to solvefor x,yn=0.2y[n-1]+x[n] ?
The answer to solvefor x,yn=0.2y[n-1]+x[n] is x=(y(4n+1))/(5n);\quad n\ne 0