What is the answer to solvefor x,y(n)=x(n)-(x-4) ?

The answer to solvefor x,y(n)=x(n)-(x-4) is x=(ny-4)/(n-1);\quad n\ne 1

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solvefor x,y(n)=x(n)-(x-4)

solve for

x, y (n) = x (n) - (x - 4)

x = \frac{n y - 4}{n - 1}; n \neq = 1

Solution steps

y (n) = x (n) - (x - 4)

Switch sides

x n - (x - 4) = y n

n x - (x - 4) = n y

Expand

n x - (x - 4) : n x - x + 4

n x - x + 4 = n y

Move

4

to the right side

n x - x = n y - 4

Factor

n x - x : x (n - 1)

x (n - 1) = n y - 4

Divide both sides by

n - 1; n \neq = 1

x = \frac{n y - 4}{n - 1}; n \neq = 1

x, x^{0} y = x y + 2 x + 2 y + 3

- 29 x + 5 a = - 29

(n - 15) (c + 3) = 20

f = (a^{2} + 16)^{2} - (a^{2} - 16)^{2}

7 x + 2 x - 15 + 69 = - 3 x + 10 x - 54

What is the answer to solvefor x,y(n)=x(n)-(x-4) ?
The answer to solvefor x,y(n)=x(n)-(x-4) is x=(ny-4)/(n-1);\quad n\ne 1