What is the answer to solvefor z,p^3+q^3=27z ?

The answer to solvefor z,p^3+q^3=27z is z=(p^3+q^3)/(27)

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solvefor z,p^3+q^3=27z

solve for

z, p^{3} + q^{3} = 27 z

z = \frac{p ^{3} + q ^{3}}{27}

Solution steps

p^{3} + q^{3} = 27 z

Switch sides

27 z = p^{3} + q^{3}

Divide both sides by

27

z = \frac{p ^{3} + q ^{3}}{27}

a, \frac{6}{9} a = \frac{b}{6}

x, x - 40 y - 240 = 0

p, r = p + q - p + 10

x, 3 x + 5 y = 4 y

h + 3 = - 4

What is the answer to solvefor z,p^3+q^3=27z ?
The answer to solvefor z,p^3+q^3=27z is z=(p^3+q^3)/(27)