What is the answer to (y^1)^1+y^1+y=0 ?

The answer to (y^1)^1+y^1+y=0 is y=0

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(y^1)^1+y^1+y=0

(y^{1})^{1} + y^{1} + y = 0

y = 0

Solution steps

(y^{1})^{1} + y^{1} + y = 0

Apply rule

a^{1} = a

(y^{1})^{1} = y^{1}, y^{1} = y

y^{1} + y + y = 0

Add similar elements:

y + y = 2 y

y^{1} + 2 y = 0

Apply rule

a^{1} = a

y + 2 y = 0

Add similar elements:

y + 2 y = 3 y

3 y = 0

Divide both sides by

3

y = 0

x, y - 2 = - 4 (x - 3)

x, \frac{x}{3} + \frac{y}{5} = 7

0.2 x + 2.1 = 5.3 - 0.8 x

0.3 (6 y - 4) = 0.09 (3 y + 5)

3 b = [\frac{( 4 ! 15 ! )}{( 7 ! 13 ! )}]^{3!}