What is the answer to solvefor n,f=f(n-1)+f(n-2) ?

The answer to solvefor n,f=f(n-1)+f(n-2) is n=2;\quad f\ne 0

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solvefor n,f=f(n-1)+f(n-2)

solve for

n, f = f (n - 1) + f (n - 2)

n = 2; f \neq = 0

Solution steps

f = f (n - 1) + f (n - 2)

Switch sides

f (n - 1) + f (n - 2) = f

Expand

f (n - 1) + f (n - 2) : 2 n f - 3 f

2 n f - 3 f = f

Move

3 f

to the right side

2 n f = 4 f

Divide both sides by

2 f; f \neq = 0

n = 2; f \neq = 0

3 x + 8 = 43 - 2 x

\frac{x + 3}{4} = \frac{11}{4}

z, p (1 + q^{2}) = q (z - 1)

p, 3 q + p = 10

0.12 (2 x - 5) + 3 x = 81

What is the answer to solvefor n,f=f(n-1)+f(n-2) ?
The answer to solvefor n,f=f(n-1)+f(n-2) is n=2;\quad f\ne 0