What is the answer to r=((2^{n+4}+2(2^n)))/(3(2^n)) ?

The answer to r=((2^{n+4}+2(2^n)))/(3(2^n)) is r=6

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r=((2^{n+4}+2(2^n)))/(3(2^n))

r = \frac{( 2 ^{n + 4} + 2 ( 2 ^{n} ) )}{3 ( 2 ^{n} )}

r = 6

Solution steps

r = \frac{( 2 ^{n + 4} + 2 ( 2 ^{n} ) )}{3 ( 2 ^{n} )}

Simplify

\frac{2 ^{n + 4} + 2 ( 2 ^{n} )}{3 ( 2 ^{n} )} : 6

r = 6

- 9 y - 8 + 3 y + 7 = - 7 y + 8 y - 5 y + 9

2 x + 10 = 24

x, 2 x + 5 y - z = 30

2 n^{2} + 3 n - 2 \cdot (n - 1)^{2} - 3 (n - 1) = 4 n + 1

2 \frac{x}{6} + \frac{45}{12} = \frac{67}{12}

What is the answer to r=((2^{n+4}+2(2^n)))/(3(2^n)) ?
The answer to r=((2^{n+4}+2(2^n)))/(3(2^n)) is r=6