What are the solutions to the equation s^2-5s+4=0 ?

The solutions to the equation s^2-5s+4=0 are s=4,s=1

Find the zeros of s^2-5s+4=0

The zeros of s^2-5s+4=0 are s=4,s=1

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s^{2} - 5 s + 4 = 0

s = 4, s = 1

Solution steps

s^{2} - 5 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

s_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, s_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

s = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

s = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

s = 4, s = 1

18 y^{3} - 50 y

\frac{3 x + 6}{x ( x - 4 )} \leq 0

m^{2} + 5 m

6 = \frac{1}{3} x + 5

∣ x - 3 ∣ = 8

What are the solutions to the equation s^2-5s+4=0 ?
The solutions to the equation s^2-5s+4=0 are s=4,s=1
Find the zeros of s^2-5s+4=0
The zeros of s^2-5s+4=0 are s=4,s=1