What is the answer to (x-3)^2+(x-1)^2=(2x-1)(x+3) ?

The answer to (x-3)^2+(x-1)^2=(2x-1)(x+3) is x=1

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(x-3)^2+(x-1)^2=(2x-1)(x+3)

(x - 3)^{2} + (x - 1)^{2} = (2 x - 1) (x + 3)

x = 1

Solution steps

(x - 3)^{2} + (x - 1)^{2} = (2 x - 1) (x + 3)

Expand

(x - 3)^{2} + (x - 1)^{2} : 2 x^{2} - 8 x + 10

Expand

(2 x - 1) (x + 3) : 2 x^{2} + 5 x - 3

2 x^{2} - 8 x + 10 = 2 x^{2} + 5 x - 3

Move

10

to the right side

2 x^{2} - 8 x = 2 x^{2} + 5 x - 13

Subtract

2 x^{2} + 5 x

from both sides

2 x^{2} - 8 x - (2 x^{2} + 5 x) = 2 x^{2} + 5 x - 13 - (2 x^{2} + 5 x)

Simplify

- 13 x = - 13

Divide both sides by

- 13

x = 1

217 - x = x - 7

2 - 3 (3 x + 1) = 2 (7 - 6 x)

\frac{( y - 9235 )}{5} = 2153

\frac{61}{3} - \frac{( x - 7 )}{3} = \frac{( 4 x - 2 )}{5}

l - c = 28 + 3 c

What is the answer to (x-3)^2+(x-1)^2=(2x-1)(x+3) ?
The answer to (x-3)^2+(x-1)^2=(2x-1)(x+3) is x=1
Solve for x: (x-3)^2+(x-1)^2=(2x-1)(x+3)
The solution is x=1