What is the answer to solvefor x,(1+y)p+(1+x)q=z ?

The answer to solvefor x,(1+y)p+(1+x)q=z is x=(z-p(1+y))/q-1;\quad q\ne 0

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solvefor x,(1+y)p+(1+x)q=z

solve for

x, (1 + y) p + (1 + x) q = z

x = \frac{z - p ( 1 + y )}{q} - 1; q \neq = 0

Solution steps

(1 + y) p + (1 + x) q = z

Move

(1 + y) p

to the right side

(1 + x) q = z - (1 + y) p

Divide both sides by

q; q \neq = 0

1 + x = \frac{z - p ( 1 + y )}{q}; q \neq = 0

Move

1

to the right side

x = \frac{z - p ( 1 + y )}{q} - 1; q \neq = 0

1 1^{10.15} - 1 1^{11} (x - 5) = 11 4^{10}

t, r + t + 2 s = 0

a, a (c + m) = 2 (c + 3 m)

y, x = \frac{( y - 18 )}{9}

x, 5 x - 7 y = - 19

What is the answer to solvefor x,(1+y)p+(1+x)q=z ?
The answer to solvefor x,(1+y)p+(1+x)q=z is x=(z-p(1+y))/q-1;\quad q\ne 0