What is the answer to log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4) ?

The answer to log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4) is x=6

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log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4)

lo g_{10} (1.6) (3 x - 16) = lo g_{10} (1.6) (x - 4)

x = 6

Solution steps

lo g_{10} (1.6) (3 x - 16) = lo g_{10} (1.6) (x - 4)

Expand

lo g_{10} (1.6) (3 x - 16) : 3 lo g_{10} (1.6) x - 16 lo g_{10} (1.6)

Expand

lo g_{10} (1.6) (x - 4) : lo g_{10} (1.6) x - 4 lo g_{10} (1.6)

3 lo g_{10} (1.6) x - 16 lo g_{10} (1.6) = lo g_{10} (1.6) x - 4 lo g_{10} (1.6)

Move

16 lo g_{10} (1.6)

to the right side

3 lo g_{10} (1.6) x = lo g_{10} (1.6) x + 12 lo g_{10} (1.6)

Move

lo g_{10} (1.6) x

to the left side

2 lo g_{10} (1.6) x = 12 lo g_{10} (1.6)

Divide both sides by

2 lo g_{10} (1.6)

x = 6

x, - 8 x + 14 y = - 20

3 (x + 3) = 2 x + n

x, - x + 3 y = 16

x, 3 x + y = 240

r (m) = 36 m^{6} - 39 m^{4} - 12 m^{2}

What is the answer to log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4) ?
The answer to log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4) is x=6
Solve for x: log_{10}(1.6)(3x-16)=log_{10}(1.6)(x-4)
The solution is x=6