What are the solutions to the equation 1/2 t^2-25=0 ?

The solutions to the equation 1/2 t^2-25=0 are t=5sqrt(2),t=-5sqrt(2)

Find the zeros of 1/2 t^2-25=0

The zeros of 1/2 t^2-25=0 are t=5sqrt(2),t=-5sqrt(2)

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\frac{1}{2} t^{2} - 25 = 0

t = 52, t = - 52

Decimal Notation

t = 7.07106 \dots, t = - 7.07106 \dots

Solution steps

\frac{1}{2} t^{2} - 25 = 0

Move

25

to the right side

\frac{1}{2} t^{2} = 25

Multiply both sides by

2

t^{2} = 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 50, t = - 50

50 = 52

- 50 = - 52

t = 52, t = - 52

2 y^{4} - y^{3} + 4 y - 2

\frac{2}{5} x + 7 = \frac{5}{2} x + 3

6 (y - 1) + 8 = 32

\frac{10}{6} \cdot \frac{6}{15}

1500 \frac{1 - ( 1 + \frac{6%}{4} ) ^{- 6.5 (4)}}{\frac{6%}{4}}

What are the solutions to the equation 1/2 t^2-25=0 ?
The solutions to the equation 1/2 t^2-25=0 are t=5sqrt(2),t=-5sqrt(2)
Find the zeros of 1/2 t^2-25=0
The zeros of 1/2 t^2-25=0 are t=5sqrt(2),t=-5sqrt(2)