What is the answer to solvefor x,y=f(x+1)-4 ?

The answer to solvefor x,y=f(x+1)-4 is x=(y+4)/f-1;\quad f\ne 0

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solvefor x,y=f(x+1)-4

solve for

x, y = f (x + 1) - 4

x = \frac{y + 4}{f} - 1; f \neq = 0

Solution steps

y = f (x + 1) - 4

Switch sides

f (x + 1) - 4 = y

Move

4

to the right side

f (x + 1) = y + 4

Divide both sides by

f; f \neq = 0

x + 1 = \frac{y + 4}{f}; f \neq = 0

Move

1

to the right side

x = \frac{y + 4}{f} - 1; f \neq = 0

x, x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

x \frac{1}{3} + 2 x \frac{2}{3} - x = 0

x, y + 2 = \frac{3}{- 10} \cdot (x - 3)

x, 3 y = \frac{1}{2} x

\frac{( \frac{4}{3} ) ^{4}}{( ( \frac{4}{3} ) ^{2} ) - 1} \cdot x = 7

What is the answer to solvefor x,y=f(x+1)-4 ?
The answer to solvefor x,y=f(x+1)-4 is x=(y+4)/f-1;\quad f\ne 0