What is the answer to (6y-2)/3 =(10+3y-y-11)/2 ?

The answer to (6y-2)/3 =(10+3y-y-11)/2 is y= 1/6

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(6y-2)/3 =(10+3y-y-11)/2

\frac{6 y - 2}{3} = \frac{10 + 3 y - y - 11}{2}

y = \frac{1}{6}

Decimal Notation

y = 0.16666 \dots

Solution steps

\frac{6 y - 2}{3} = \frac{10 + 3 y - y - 11}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(6 y - 2) \cdot 2 = 3 (10 + 3 y - y - 11)

Simplify

(6 y - 2) \cdot 2 = 3 (2 y - 1)

Expand

(6 y - 2) \cdot 2 : 12 y - 4

Expand

3 (2 y - 1) : 6 y - 3

12 y - 4 = 6 y - 3

Move

4

to the right side

12 y = 6 y + 1

Move

6 y

to the left side

6 y = 1

Divide both sides by

6

y = \frac{1}{6}

x, y = f (x + 7)

x - 2 = 3, y + 1 = 4 z + 6, a = 5

5 + 3 (x - 1) = 5 x - 6

4 (1 x + 4) = 2 (1 x + 2)

x, f = \frac{( h ^{2} + 1 )}{h}

What is the answer to (6y-2)/3 =(10+3y-y-11)/2 ?
The answer to (6y-2)/3 =(10+3y-y-11)/2 is y= 1/6
Solve for y: (6y-2)/3 =(10+3y-y-11)/2
The solution is y= 1/6