What is the answer to a=((5^2+5))/3-((2^3+2^0))/3 ?

The answer to a=((5^2+5))/3-((2^3+2^0))/3 is a=7

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a=((5^2+5))/3-((2^3+2^0))/3

a = \frac{( 5 ^{2} + 5 )}{3} - \frac{( 2 ^{3} + 2 ^{0} )}{3}

a = 7

Solution steps

a = \frac{( 5 ^{2} + 5 )}{3} - \frac{( 2 ^{3} + 2 ^{0} )}{3}

Simplify

\frac{5 ^{2} + 5}{3} - \frac{2 ^{3} + 2 ^{0}}{3} : 7

a = 7

f = 2 (2.5)^{2} - 6 (2.5) + 16

10 + (x - 2) = 5 - (x - 4)

5 x - 3 = a - 18

\frac{- 4 x + 1}{2} = \frac{31}{2}

b, 3 b = 6 c + b - 2 c + 0.5 b

What is the answer to a=((5^2+5))/3-((2^3+2^0))/3 ?
The answer to a=((5^2+5))/3-((2^3+2^0))/3 is a=7
Solve for a: a=((5^2+5))/3-((2^3+2^0))/3
The solution is a=7