What is the answer to ((3x-1)}{3+75}=\frac{(x+1))/3 ?

The answer to ((3x-1)}{3+75}=\frac{(x+1))/3 is x=-27/23

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((3x-1)}{3+75}=\frac{(x+1))/3

\frac{( 3 x - 1 )}{3 + 75} = \frac{( x + 1 )}{3}

x = - \frac{27}{23}

Decimal Notation

x = - 1.17391 \dots

Solution steps

\frac{( 3 x - 1 )}{3 + 75} = \frac{( x + 1 )}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 x - 1) \cdot 3 = (3 + 75) (x + 1)

Simplify

(3 x - 1) \cdot 3 = 78 (x + 1)

Expand

(3 x - 1) \cdot 3 : 9 x - 3

Expand

78 (x + 1) : 78 x + 78

9 x - 3 = 78 x + 78

Move

3

to the right side

9 x = 78 x + 81

Move

78 x

to the left side

- 69 x = 81

Divide both sides by

- 69

x = - \frac{27}{23}

(x + 2) (x + 3) (x - 1) = (x + 4) (x + 4) (x - 4) - 27

0.32 x = 3

415 + (164 - x) = 501

x, - 3 x - 9 y = 0

x, x + 10 y + 27 = y + 10 x

What is the answer to ((3x-1)}{3+75}=\frac{(x+1))/3 ?
The answer to ((3x-1)}{3+75}=\frac{(x+1))/3 is x=-27/23
Solve for x: ((3x-1)}{3+75}=\frac{(x+1))/3
The solution is x=-27/23