What is the answer to a=[25+((17/18-5/12))/3*1/6 ]*0a ?

The answer to a=[25+((17/18-5/12))/3*1/6 ]*0a is a=0

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a=[25+((17/18-5/12))/31/6 ]0a

a = [25 + \frac{( \frac{17}{18} - \frac{5}{12} )}{3} \cdot \frac{1}{6}] \cdot 0 a

a = 0

Solution steps

a = [25 + \frac{( \frac{17}{18} - \frac{5}{12} )}{3} \cdot \frac{1}{6}] \cdot 0 \cdot a

Expand

(25 + \frac{\frac{17}{18} - \frac{5}{12}}{3} \cdot \frac{1}{6}) \cdot 0 \cdot a : 0

a = 0

3 (\frac{x}{2 - 4}) = 5

\frac{2}{3} x - \frac{1}{2} = \frac{3}{4}

x, 3 x + 4 y = 5

\frac{x}{4} - \frac{x}{2} = 3 \frac{1}{3} - \frac{x}{3}

x, (y - 5) = 2 [x - (3)]

What is the answer to a=[25+((17/18-5/12))/3*1/6 ]*0a ?
The answer to a=[25+((17/18-5/12))/3*1/6 ]*0a is a=0
Solve for a: a=[25+((17/18-5/12))/3*1/6 ]*0a
The solution is a=0