What is the answer to solvefor x,(x-3)2+(y+12)2=1 ?

The answer to solvefor x,(x-3)2+(y+12)2=1 is x=(-2y-23)/2+3

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solvefor x,(x-3)2+(y+12)2=1

solve for

x, (x - 3) 2 + (y + 12) 2 = 1

x = \frac{- 2 y - 23}{2} + 3

Solution steps

(x - 3) \cdot 2 + (y + 12) \cdot 2 = 1

Move

(y + 12) 2

to the right side

(x - 3) \cdot 2 = - 2 y - 23

Divide both sides by

2

x - 3 = \frac{- 2 y - 23}{2}

Move

3

to the right side

x = \frac{- 2 y - 23}{2} + 3

\frac{x}{a} + \frac{x}{b} + \frac{x}{c} = 1

j, f = 2 i + 5 j + 6 k

x, 5 x^{1} = o^{3} x - 1

l = 2 r

d, z = m o d z + z^{2}

What is the answer to solvefor x,(x-3)2+(y+12)2=1 ?
The answer to solvefor x,(x-3)2+(y+12)2=1 is x=(-2y-23)/2+3