What is the answer to solvefor x,y^{0.12}=6x+3y ?

The answer to solvefor x,y^{0.12}=6x+3y is x=(y^{0.12}-3y)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y^{0.12}=6x+3y

solve for

x, y^{0.12} = 6 x + 3 y

x = \frac{y ^{0.12} - 3 y}{6}

Solution steps

y^{0.12} = 6 x + 3 y

Switch sides

6 x + 3 y = y^{0.12}

Move

3 y

to the right side

6 x = y^{0.12} - 3 y

Divide both sides by

6

x = \frac{y ^{0.12} - 3 y}{6}

x, 5 x + 3 y = 95

\frac{x}{2 + 1} = x

3 + \frac{x}{4} = \frac{1}{2} \cdot (4 - \frac{x}{3}) - \frac{5}{6} + \frac{1}{3} \cdot (11 - \frac{x}{2})

\frac{x}{3} + x + \frac{1}{4} = 9

x, 2 x + 3 y = 12 y

What is the answer to solvefor x,y^{0.12}=6x+3y ?
The answer to solvefor x,y^{0.12}=6x+3y is x=(y^{0.12}-3y)/6