What are the solutions to the equation 2x^2+x=6 ?

The solutions to the equation 2x^2+x=6 are x= 3/2 ,x=-2

Find the zeros of 2x^2+x=6

The zeros of 2x^2+x=6 are x= 3/2 ,x=-2

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2 x^{2} + x = 6

x = \frac{3}{2}, x = - 2

Decimal Notation

x = 1.5, x = - 2

Solution steps

2 x^{2} + x = 6

Move

6

to the left side

2 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 2}, x_{2} = \frac{- 1 - 7}{2 \cdot 2}

x = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 2

3 x^{3} + 5 x^{2} - 4 x - 4

x + 3 < 0 or 3 x > - 6

- 1 + \frac{x}{2} = 9

2 x + 8

\frac{7 x}{2} + 5 = 6 x

What are the solutions to the equation 2x^2+x=6 ?
The solutions to the equation 2x^2+x=6 are x= 3/2 ,x=-2
Find the zeros of 2x^2+x=6
The zeros of 2x^2+x=6 are x= 3/2 ,x=-2