What is the answer to solvefor a,n(p(p(a)))-n(p(b))=255 ?

The answer to solvefor a,n(p(p(a)))-n(p(b))=255 is a=(255+npb)/(np^2);\quad p\ne 0

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solvefor a,n(p(p(a)))-n(p(b))=255

solve for

a, n (p (p (a))) - n (p (b)) = 255

a = \frac{255 + n p b}{n p ^{2}}; p \neq = 0

Solution steps

n (p (p (a))) - n (p (b)) = 255

Simplify

n (p (p (a))) - n (p (b)) : na p^{2} - n p b

na p^{2} - n p b = 255

Move

n p b

to the right side

na p^{2} = 255 + n p b

Divide both sides by

n p^{2}; p \neq = 0

a = \frac{255 + n p b}{n p ^{2}}; p \neq = 0

1.25 x = 512

\frac{x}{4} = 0.5

a, a - b + 2 c = 2

f, (i) \cdot f = 11 x^{2} - 6 x^{3} + 9

x, 2 x - 3 - m = m

What is the answer to solvefor a,n(p(p(a)))-n(p(b))=255 ?
The answer to solvefor a,n(p(p(a)))-n(p(b))=255 is a=(255+npb)/(np^2);\quad p\ne 0