What is the answer to -2=3,x+2y+3z=6-(3),2x+y-2=3 ?

The answer to -2=3,x+2y+3z=6-(3),2x+y-2=3 is False

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-2=3,x+2y+3z=6-(3),2x+y-2=3

- 2 = 3, x + 2 y + 3 z = 6 - (3), 2 x + y - 2 = 3

False

Solution steps

- 2 = 3

The sides are not equal

False

b 0.3 (\frac{y}{2 + 6}) = 7 (\frac{y}{3 + 9})

(a) \frac{1}{4} \cdot 38 = \frac{1}{4} \cdot 18 + \frac{1}{4}

x, y - 16 = 3 x - 48

0.75 \cdot 6.8 + 0.25 \cdot x = 6

r = \frac{n ( n + 1 )}{2 \cdot 12}

What is the answer to -2=3,x+2y+3z=6-(3),2x+y-2=3 ?
The answer to -2=3,x+2y+3z=6-(3),2x+y-2=3 is False