What is the answer to solvefor x,(y-x)p+(2-x)y=x-y ?

The answer to solvefor x,(y-x)p+(2-x)y=x-y is x=-(-py-3y)/(1+p+y);\quad p\ne-y-1

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solvefor x,(y-x)p+(2-x)y=x-y

solve for

x, (y - x) p + (2 - x) y = x - y

x = - \frac{- p y - 3 y}{1 + p + y}; p \neq = - y - 1

Solution steps

(y - x) p + (2 - x) y = x - y

Expand

(y - x) p + (2 - x) y : p y - p x + 2 y - x y

p y - p x + 2 y - x y = x - y

Move

p y

to the right side

- p x + 2 y - x y = x - y - p y

Move

2 y

to the right side

- p x - x y = - p y - 3 y + x

Move

x

to the left side

- p x - x y - x = - p y - 3 y

Factor

- p x - x y - x : - x (p + y + 1)

- x (p + y + 1) = - p y - 3 y

Divide both sides by

- (p + y + 1); p \neq = - y - 1

x = - \frac{- p y - 3 y}{1 + p + y}; p \neq = - y - 1

y, x = lo g_{3} (lo g_{2} (512)) \cdot y

3 x + 2 (x - 3) = 4 (2 + x)

t (n) = t (n) + 2

f, 17 f = x^{3} + y^{3} + 3 x^{2} - 18 y^{2} + 81 y + 5

x, x + 6 y = 277 x - 3

What is the answer to solvefor x,(y-x)p+(2-x)y=x-y ?
The answer to solvefor x,(y-x)p+(2-x)y=x-y is x=-(-py-3y)/(1+p+y);\quad p\ne-y-1