What is the answer to t(n)=8t(n-1)+15t(n-2) ?

The answer to t(n)=8t(n-1)+15t(n-2) is t=0

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t(n)=8t(n-1)+15t(n-2)

t (n) = 8 t (n - 1) + 15 t (n - 2)

t = 0

Solution steps

t (n) = 8 t (n - 1) + 15 t (n - 2)

Expand

t (n) : n t

Expand

8 t (n - 1) + 15 t (n - 2) : 23 n t - 38 t

n t = 23 n t - 38 t

Subtract

23 n t - 38 t

from both sides

n t - (23 n t - 38 t) = 23 n t - 38 t - (23 n t - 38 t)

Simplify

- 22 n t + 38 t = 0

Factor

- 22 n t + 38 t : 2 t (- 11 n + 19)

2 t (- 11 n + 19) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0

x, x y^{3} - y (2 + y)^{2} = 2 x

x, y - \frac{11}{7} = \frac{4}{7} (x - \frac{16}{7})

5 x = \frac{3 x - 3}{5}

x, x + y + 2 y = 9

t (n) = 5 t (n - 1) - 6 t (n - 2)

What is the answer to t(n)=8t(n-1)+15t(n-2) ?
The answer to t(n)=8t(n-1)+15t(n-2) is t=0