What is the answer to ((2x-1))/5-((3x+1))/2 = 20/3-2x ?

The answer to ((2x-1))/5-((3x+1))/2 = 20/3-2x is x= 221/27

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((2x-1))/5-((3x+1))/2 = 20/3-2x

\frac{( 2 x - 1 )}{5} - \frac{( 3 x + 1 )}{2} = \frac{20}{3} - 2 x

x = \frac{221}{27}

Decimal Notation

x = 8.18518 \dots

Solution steps

\frac{( 2 x - 1 )}{5} - \frac{( 3 x + 1 )}{2} = \frac{20}{3} - 2 x

\frac{2 x - 1}{5} - \frac{3 x + 1}{2} = \frac{20}{3} - 2 x

Multiply by LCM

6 (2 x - 1) - 15 (3 x + 1) = 200 - 60 x

Expand

6 (2 x - 1) - 15 (3 x + 1) : - 33 x - 21

- 33 x - 21 = 200 - 60 x

Move

21

to the right side

- 33 x = - 60 x + 221

Move

60 x

to the left side

27 x = 221

Divide both sides by

27

x = \frac{221}{27}

x, y - 1 = \frac{1}{4} \cdot (x - 12)

x, 12 x + 2 y + z = 120000

x + \frac{2}{2} - x + \frac{4}{4} = 2 + \frac{1}{4}

x - 8 = \cdot 3

x, - 6 x + y = 5

What is the answer to ((2x-1))/5-((3x+1))/2 = 20/3-2x ?
The answer to ((2x-1))/5-((3x+1))/2 = 20/3-2x is x= 221/27
Solve for x: ((2x-1))/5-((3x+1))/2 = 20/3-2x
The solution is x= 221/27