What is the answer to [(x-1)^2-(x+1)^2]^2=(4x-3)^2 ?

The answer to [(x-1)^2-(x+1)^2]^2=(4x-3)^2 is x= 3/8

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[(x-1)^2-(x+1)^2]^2=(4x-3)^2

[(x - 1)^{2} - (x + 1)^{2}]^{2} = (4 x - 3)^{2}

x = \frac{3}{8}

Decimal Notation

x = 0.375

Solution steps

[(x - 1)^{2} - (x + 1)^{2}]^{2} = (4 x - 3)^{2}

Expand

((x - 1)^{2} - (x + 1)^{2})^{2} : 16 x^{2}

Expand

(4 x - 3)^{2} : 16 x^{2} - 24 x + 9

16 x^{2} = 16 x^{2} - 24 x + 9

Subtract

16 x^{2} - 24 x

from both sides

16 x^{2} - (16 x^{2} - 24 x) = 16 x^{2} - 24 x + 9 - (16 x^{2} - 24 x)

Simplify

24 x = 9

Divide both sides by

24

x = \frac{3}{8}

x, 3 x + 5 y = 40 5^{2}

17 x - 5 = 2 x

2 (12 + x) = 41 + x

x, (y - 5) = 2 [x - (- 3)]

x, 2 x + 10 = 2 y - 8

What is the answer to [(x-1)^2-(x+1)^2]^2=(4x-3)^2 ?
The answer to [(x-1)^2-(x+1)^2]^2=(4x-3)^2 is x= 3/8
Solve for x: [(x-1)^2-(x+1)^2]^2=(4x-3)^2
The solution is x= 3/8