What is the answer to solvefor a, 5/((x+1))=a|x-4| ?

The answer to solvefor a, 5/((x+1))=a|x-4| is a= 5/(|x-4|(x+1));\quad x\ne 4

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solvefor a, 5/((x+1))=a|x-4|

solve for

a, \frac{5}{( x + 1 )} = a ∣ x - 4 ∣

a = \frac{5}{∣ x - 4 ∣ ( x + 1 )}; x \neq = 4

Solution steps

\frac{5}{( x + 1 )} = a ∣ x - 4 ∣

Switch sides

a ∣ x - 4 ∣ = \frac{5}{x + 1}

a ∣ x - 4 ∣ = \frac{5}{x + 1}

Divide both sides by

∣ x - 4 ∣; x \neq = 4

a = \frac{5}{∣ x - 4 ∣ ( x + 1 )}; x \neq = 4

(2 - 3 i) \cdot x = (2 + 3 i)

y, \frac{y}{2} = \frac{( z - 11 )}{- 1}

4 e^{2} x = 5

x - 1 = 3 x

165 = a

What is the answer to solvefor a, 5/((x+1))=a|x-4| ?
The answer to solvefor a, 5/((x+1))=a|x-4| is a= 5/(|x-4|(x+1));\quad x\ne 4