What is the answer to 0.003(k-4)+0.08(k-7)=1 ?

The answer to 0.003(k-4)+0.08(k-7)=1 is k= 1572/83

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0.003(k-4)+0.08(k-7)=1

0.003 (k - 4) + 0.08 (k - 7) = 1

k = \frac{1572}{83}

Decimal Notation

k = 18.93975 \dots

Solution steps

0.003 (k - 4) + 0.08 (k - 7) = 1

Multiply both sides by

1000

3 (k - 4) + 80 (k - 7) = 1000

Expand

3 (k - 4) + 80 (k - 7) : 83 k - 572

83 k - 572 = 1000

Move

572

to the right side

83 k = 1572

Divide both sides by

83

k = \frac{1572}{83}

5 r + 15 = 2.5 r

a^{2} x + 1 = (\frac{1}{a})^{8}

x, 5 x + 6 i = - 20 + 2 y

5 x + 5 = \frac{3}{7}

7 \cdot 1 7^{- 9} x - 7 = 49

What is the answer to 0.003(k-4)+0.08(k-7)=1 ?
The answer to 0.003(k-4)+0.08(k-7)=1 is k= 1572/83
Solve for k: 0.003(k-4)+0.08(k-7)=1
The solution is k= 1572/83