What is the answer to sqrt(b)x-2=3x+22 ?

The answer to sqrt(b)x-2=3x+22 is x=(24(sqrt(b)+3))/(b-9);\quad b\ne 9

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sqrt(b)x-2=3x+22

b x - 2 = 3 x + 22

x = \frac{24 ( b + 3 )}{b - 9}; b \neq = 9

Solution steps

b x - 2 = 3 x + 22

Move

2

to the right side

b x = 3 x + 24

Move

3 x

to the left side

b x - 3 x = 24

Factor

b x - 3 x : x (b - 3)

x (b - 3) = 24

Divide both sides by

b - 3; b \neq = 9

x = \frac{24 ( b + 3 )}{b - 9}; b \neq = 9

x, - 6 x - 4 y = - 16

a, \frac{3}{c} \cdot a - \frac{1}{4} \cdot b = a + b (- 1 + m)

x - 0.1 x = 8.1 x

x, \frac{x}{y} = 4

4 x (7 x - 5) - 7 x (4 x - 2) = - 12

What is the answer to sqrt(b)x-2=3x+22 ?
The answer to sqrt(b)x-2=3x+22 is x=(24(sqrt(b)+3))/(b-9);\quad b\ne 9