What is the answer to solvefor p,3q-300p+1800=0 ?

The answer to solvefor p,3q-300p+1800=0 is p=(q+600)/(100)

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solvefor p,3q-300p+1800=0

solve for

p, 3 q - 300 p + 1800 = 0

p = \frac{q + 600}{100}

Solution steps

3 q - 300 p + 1800 = 0

Move

3 q

to the right side

- 300 p + 1800 = - 3 q

Move

1800

to the right side

- 300 p = - 3 q - 1800

Divide both sides by

- 300

p = \frac{q + 600}{100}

j, a = 3 i - j + 7 k

1.63 l_{2} + l_{2} = 25

x, 3 y - 2 x - 1 = 0

x, x y + 2 = x + 2 y

a, (a + b + c) (a - b + c) = a^{2} + b^{2} + c^{2}

What is the answer to solvefor p,3q-300p+1800=0 ?
The answer to solvefor p,3q-300p+1800=0 is p=(q+600)/(100)