What is the answer to (a^2-9)*x=a^3+27 ?

The answer to (a^2-9)*x=a^3+27 is x=(a^2-3a+9)/(a-3);\quad a\ne 3,a\ne-3

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(a^2-9)*x=a^3+27

(a^{2} - 9) \cdot x = a^{3} + 27

x = \frac{a ^{2} - 3 a + 9}{a - 3}; a \neq = 3, a \neq = - 3

Solution steps

(a^{2} - 9) x = a^{3} + 27

Divide both sides by

a^{2} - 9; a \neq = 3, a \neq = - 3

x = \frac{a ^{2} - 3 a + 9}{a - 3}; a \neq = 3, a \neq = - 3

v = 3 \cdot 9.8

\frac{y}{( 1 + p ^{2} )} = 1

x, x - 6 y = 1

\frac{( 2 x - 9 )}{5} - \frac{3}{10} = \frac{( 4 x - 8 )}{10} + 2

\frac{0.4 x + x}{3} = 0.2 x + 6

What is the answer to (a^2-9)*x=a^3+27 ?
The answer to (a^2-9)*x=a^3+27 is x=(a^2-3a+9)/(a-3);\quad a\ne 3,a\ne-3