What is the answer to solvefor x,(5a+1)x-20y-2=0 ?

The answer to solvefor x,(5a+1)x-20y-2=0 is x=(20y+2)/(5a+1);\quad a\ne-1/5

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solvefor x,(5a+1)x-20y-2=0

solve for

x, (5 a + 1) x - 20 y - 2 = 0

x = \frac{20 y + 2}{5 a + 1}; a \neq = - \frac{1}{5}

Solution steps

(5 a + 1) x - 20 y - 2 = 0

Move

20 y

to the right side

(5 a + 1) x - 2 = 20 y

Move

2

to the right side

(5 a + 1) x = 20 y + 2

Divide both sides by

5 a + 1; a \neq = - \frac{1}{5}

x = \frac{20 y + 2}{5 a + 1}; a \neq = - \frac{1}{5}

\frac{y + 53}{4} = 10

\frac{a - 1}{a} = n

x, f - g = 0

93 (5 z - 7) - 2 (9 z - 11) = 4 (8 z - 13) - 17

b = 1 7^{2} - 8^{2} + 3 3 8^{2} - 3 7^{2}

What is the answer to solvefor x,(5a+1)x-20y-2=0 ?
The answer to solvefor x,(5a+1)x-20y-2=0 is x=(20y+2)/(5a+1);\quad a\ne-1/5